P=-0.1x^2+27x+1,700

Solution for P=-0.1x^2+27x+1,700 equation:

=-0.1P^2+27P+1.700

We move all terms to the left:

-(-0.1P^2+27P+1.700)=0

We get rid of parentheses

0.1P^2-27P-1.700=0

We add all the numbers together, and all the variables

0.1P^2-27P-1.7=0

a = 0.1; b = -27; c = -1.7;
Δ = b2-4ac
Δ = -272-4·0.1·(-1.7)
Δ = 729.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{729.68}}{2*0.1}=\frac{27-\sqrt{729.68}}{0.2}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{729.68}}{2*0.1}=\frac{27+\sqrt{729.68}}{0.2}
$